Alfred topographic map

Click on the map to display elevation.

Alfred

The elevation of Alfred is about 1,700 feet (520 m) but rises to a high point of 2,355 feet (718 m) at the summit of Jericho Hill just south of the village. The hills greatly affect the weather in the region, which results in quick changes as well as different conditions in neighboring valleys.

About this map

Name: Alfred topographic map, elevation, terrain.

Location: Alfred, Town of Alfred, Allegany County, New York, 14802, United States (42.23423 -77.81061 42.27423 -77.77061)

Average elevation: 604 m

Minimum elevation: 484 m

Maximum elevation: 712 m